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| 1. |
In the electrolysis os a basic solution, oxygen can be produced by the half reaction
4 OH-1 O2 +
2 H2O + 4 e-1
How many moles of O2 can be produced from a solution that was electrolyzed
for 3.00 hours using a current of 8.00 amps?
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a)
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1.49 x 10-2
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b)
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4.48 x 10-2
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c)
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0.224
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d)
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0.448
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e)
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0.896
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| 2. |
What is the value of the reaction quotient, Q, for the cell that is constructed from
the two half-reactions
Zn+2 + 2 e-1 Zn
-0.76 V
Ag+1 + 1 e-1 Ag
0.80 V
when the Zn+2 concentation is 0.0100 M and the Ag+1 concentration
is 1.25 M?
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a)
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156
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b)
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125
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c)
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1.25 x 10-2
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d)
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8.00 x 10-3
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e)
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6.40 x 10-3
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| 3. |
What is the emf at 25oC for the following cell?
Cr | Cr+3 (0.010 M) || Ag+1 (0.00010 M) | Ag
Cr+3 + 3 e-1 Cr
Eo
= -0.74 V
Ag+1 + 1 e-1 Ag
Eo
= 0.80 V
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a)
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2.09 V
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b)
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1.34 V
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c)
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0.95 V
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d)
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1.74 V
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e)
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1.50 V
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| 4. |
When a solution of cesium iodide is electrolyzed, the products that would be expected
are:
Cs+1(aq) + 1 e-1
Cs(s)
Eo = -2.92 V
I2(s) + 2 e-1 2 I-1(aq)
Eo = +0.54 V
2 H2O(l) O2(g) + 4 H+1(aq)
+ 4 e-1
Eo = -1.23 V
2 H2O(l) + 2 e-1 H2(g)
+ 2 OH-1(aq)
Eo = -0.83 V
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a)
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Cs(s), I2(s).
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b)
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H2(g), OH-1(aq), Cs(s).
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c)
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H2(g), OH-1(aq), I2(s).
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d)
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O2(g), H+1(aq), I2(s).
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e)
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H2(g), OH-1(aq), O2(g), H+1(aq).
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