Chapter 14 Module 3

Kinetics Module 3

Course Name: Chemistry Course No.132 NT Teacher: Bill Cook Teacher's Email: bcook@icc.edu

No. of Questions= 3

1. For the decomposition of one mole of nitrosyl chloride, DH = -138 kJ.
NOCl_(g) Ž NO_(g) + 1/2 Cl_2(g)

The activation energy for this reaction is 85 kJ.
Sketch a potential energy diagram and determine the energy of activation for the reverse reaction?

a) +53 kJ

b) -53 kJ

c) +138 kJ

d) +223 kJ

e) -223 kJ

2. The rate constants for the decomposition of a compound are 4.2 x 10^-4 sec^-1 at 25^oC and 6.1 x 10^-3 sec^-1 at 55^oC. What is the value of the activation energy for this reaction in kJ?

a) 1.02 kJ

b) 0.72 kJ

c) 315 kJ

d) 68.3 kJ

e) 72.5 kJ

3. For a given reaction, the rate constant, k, was determined at different temperatures. To obtain a linear graph, one should plot:

a) k vs. ^oC.

b) log k vs. Kelvin.

c) ln k vs. Kelvin.

d) k vs. 1/Kelvin.

e) ln k vs. 1/Kelvin.

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1.	For the decomposition of one mole of nitrosyl chloride, DH = -138 kJ. NOCl_(g) Ž NO_(g) + 1/2 Cl_2(g) The activation energy for this reaction is 85 kJ. Sketch a potential energy diagram and determine the energy of activation for the reverse reaction?

	a)	+53 kJ
	b)	-53 kJ
	c)	+138 kJ
	d)	+223 kJ
	e)	-223 kJ


2.	The rate constants for the decomposition of a compound are 4.2 x 10^-4 sec^-1 at 25^oC and 6.1 x 10^-3 sec^-1 at 55^oC. What is the value of the activation energy for this reaction in kJ?

	a)	1.02 kJ
	b)	0.72 kJ
	c)	315 kJ
	d)	68.3 kJ
	e)	72.5 kJ


3.	For a given reaction, the rate constant, k, was determined at different temperatures. To obtain a linear graph, one should plot:

	a)	k vs. ^oC.
	b)	log k vs. Kelvin.
	c)	ln k vs. Kelvin.
	d)	k vs. 1/Kelvin.
	e)	ln k vs. 1/Kelvin.